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Worksheet Percentages and Proportions
2.
3.
4.
In last seasonβs basketball games, Ivan made \(90\%\) in free throws. If he attempted a total of \(270\) free throws, how many free throws did he make?
Ivan made free throws last season.
Solution.
This problem can be boiled down to this question: What is \(90\%\) of \(270\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(90\%\) of \(270\) is \(x\text{,}\) so β\(90\) out of \(100\)β corresponds to β\(x\) out of \(270\)β.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t]
\frac{90}{100} \amp = \frac{x}{270} \\
100x \amp = 90 \cdot 270 \\
100x \amp = 24300 \\
\frac{100x}{100} \amp = \frac{24300}{100} \\
x \amp = 243
\end{aligned}
}\)
Ivan made \(243\) free throws last season.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(90\%\) of \(270\text{?}\) Assume \(x\) is \(90\%\) of \(270\text{.}\) We have:
\(\displaystyle{
\begin{aligned}
x \amp = 0.9 \cdot 270 \\
\amp = 243
\end{aligned}
}\)
Ivan made \(243\) free throws last season.
Method 3
-
βwhatβ is the percentage,
-
\(90\%\) is the rate,
-
\(270\) is the base (following the word βofβ).
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 90\% \cdot 270 = 0.9 \cdot 270 = 243 }\)
Ivan made \(243\) free throws last season.
5.
A county has \(49500\) residents. In the last election, \(54\%\) turned out to vote. How many residents voted?
In the last election, residents in the county turned out to vote.
Solution.
This problem can be boiled down to this question: What is \(54\%\) of \(49500\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(54\%\) of \(49500\) is \(x\text{,}\) so β\(54\) out of \(100\)β corresponds to β\(x\) out of \(49500\)β.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t]
\frac{54}{100} \amp = \frac{x}{49500} \\
100x \amp = 54 \cdot 49500 \\
100x \amp = 2673000 \\
\frac{100x}{100} \amp = \frac{2673000}{100} \\
x \amp = 26730
\end{aligned}
}\)
In the last election, \(26730\) residents in the county. turned out to vote.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(54\%\) of \(49500\text{?}\) Assume \(x\) is \(54\%\) of \(49500\text{.}\) We have:
\(\displaystyle{
\begin{aligned}
x \amp = 0.54 \cdot 49500 \\
\amp = 26730
\end{aligned}
}\)
In the last election, \(26730\) residents in the county. turned out to vote.
Method 3
-
βwhatβ is the percentage,
-
\(54\%\) is the rate,
-
\(49500\) is the base (following the word βofβ).
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 54\% \cdot 49500 = 0.54 \cdot 49500 = 26730 }\)
In the last election, \(26730\) residents in the county. turned out to vote.
6.
A painting is on sale with \(35\%\) off. Its original price was \({\$400.00}\text{.}\) What is its price on sale?
The painting sells for on sale.
Solution.
The painting is \(35\%\) off, implying that its current price is \(65\%\) of its original price.
This problem can be boiled down to this question: What is \(65\%\) of \(400\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(65\%\) of \(400\) is \(x\text{,}\) so β\(65\) out of \(100\)β corresponds to β\(x\) out of \(400\)β.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t]
\frac{65}{100} \amp = \frac{x}{400} \\
100x \amp = 65 \cdot 400 \\
100x \amp = 26000 \\
\frac{100x}{100} \amp = \frac{26000}{100} \\
x \amp = 260
\end{aligned}
}\)
The painting sells for \({\$260.00}\) on sale.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(65\%\) of \(400\text{?}\) Assume \(x\) is \(65\%\) of \(400\text{.}\) We have:
\(\displaystyle{
\begin{aligned}
x \amp = 0.65 \cdot 400 \\
\amp = 260
\end{aligned}
}\)
The painting sells for \({\$260.00}\) on sale.
Method 3
-
βwhatβ is the percentage,
-
\(65\%\) is the rate,
-
\(400\) is the base (following the word βofβ).
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 65\% \cdot 400 = 0.65 \cdot 400 = 260 }\)
The painting sells for \({\$260.00}\) on sale.
7.
A watchβs wholesale price was \({\$260.00}\text{.}\) The retailer marked up the price by \(40\%\text{.}\) Whatβs the watchβs new price (markup price)?
The watchβs markup price is .
Solution.
First, we need to find the amount of increase in price. Itβs given that the watchβs price was marked up by \(40\%\) of its original price, \({\$260.00}\text{.}\)
The problem can be boiled down to this question: What is \(40\%\) of \(260\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(40\%\) of \(260\) is \(x\text{,}\) so β\(40\) out of \(100\)β corresponds to β\(x\) out of \(260\)β.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t]
\frac{40}{100} \amp = \frac{x}{260} \\
100x \amp = 40 \cdot 260 \\
100x \amp = 10400 \\
\frac{100x}{100} \amp = \frac{10400}{100} \\
x \amp = 104
\end{aligned}
}\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watchβs markup price is \({\$364.00}\text{.}\)
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(40\%\) of \(260\text{?}\) Assume \(x\) is \(40\%\) of \(260\text{.}\) We have:
\(\displaystyle{
\begin{aligned}
x \amp = 0.4 \cdot 260 \\
\amp = 104
\end{aligned}
}\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watchβs markup price is \({\$364.00}\text{.}\)
Method 3
-
βwhatβ is the percentage,
-
\(40\%\) is the rate,
-
\(260\) is the base (following the word βofβ).
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 40\% \cdot 260 = 0.4 \cdot 260 = 104 }\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watchβs markup price is \({\$364.00}\text{.}\)
8.
Write the given ratio as a fraction in simplest form.
`8` to `20=`
Reduced Fraction: numeric
9.
10.
11.
Set up a proportion to solve the application problem. Round your answer to the nearest milliliter:
Pediatricians prescribe 60 milliliters (ml) of acetaminophen for every 20 pounds of a childβs weight. How many milliliters of acetaminophen will the doctor prescribe for Jocelyn, who weighs 65 pounds?
Solution: ml (rounded to the nearest ml)
Solution.
The ratio given is:
\(\displaystyle{\frac{60 \; \textrm{ml}}{20 \; \textrm{lbs}}}\)
We can set up a ratio, making sure that the units are the same on each side.
\(\displaystyle{\frac{60 \; \textrm{ml}}{20 \; \textrm{lbs}}=\frac{x \; \textrm{ml}}{65 \; \textrm{lbs}}}\)
\(\displaystyle{\frac{60}{20}=\frac{x}{65}}\)
Set the cross products equal:
\(20x = 65\cdot60\)
\(20x = 3900\)
Divide both sides by 20.
\(x = 195\)
12.
Set up a proportion to solve the application problem. Enter a reduced fraction or integer as your final answer.
An oatmeal cookie recipe calls for \(\frac{1}{4}\) cup of butter to make 6 cookies. Hilda needs to make 42 cookies for the bake sale. How many cups of butter will she need?
Solution: cups
Solution.
Let x = the number of cups of butter that Hilda needs.
We can use the proportion:
\(\displaystyle{\frac{\frac{1}{4}}{6}=\frac{x}{42}}\)
Set the cross products equal:
\(6x = \frac{1}{4} \cdot 42\)
\(6x = \frac{1}{4} \cdot \frac{42}{1}\)
\(6x = \frac{42}{4}\)
\(x = \frac{42}{4} \div 6\)
\(x = \frac{42}{4} \cdot \frac{1}{6}\)
\(x = \frac{42}{24}\)
\(x = {{\frac{7}{4}}}\)
