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Math Trailhead

Worksheet Percentages and Proportions

3.

Convert the following percent to a fraction. Make sure to reduce your fraction to lowest terms.
\(\displaystyle{ 16\%= }\) numeric
Answer.
\({\frac{4}{25}}\)

4.

In last season’s basketball games, Ivan made \(90\%\) in free throws. If he attempted a total of \(270\) free throws, how many free throws did he make?
Ivan made free throws last season.
Answer.
Solution.
This problem can be boiled down to this question: What is \(90\%\) of \(270\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(90\%\) of \(270\) is \(x\text{,}\) so β€œ\(90\) out of \(100\)” corresponds to β€œ\(x\) out of \(270\)”.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t] \frac{90}{100} \amp = \frac{x}{270} \\ 100x \amp = 90 \cdot 270 \\ 100x \amp = 24300 \\ \frac{100x}{100} \amp = \frac{24300}{100} \\ x \amp = 243 \end{aligned} }\)
Ivan made \(243\) free throws last season.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(90\%\) of \(270\text{?}\) Assume \(x\) is \(90\%\) of \(270\text{.}\) We have:
\(\displaystyle{ \begin{aligned} x \amp = 0.9 \cdot 270 \\ \amp = 243 \end{aligned} }\)
Ivan made \(243\) free throws last season.
Method 3
In the sentence β€œWhat is \(90\%\) of \(270\text{,}\)”
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 90\% \cdot 270 = 0.9 \cdot 270 = 243 }\)
Ivan made \(243\) free throws last season.

5.

A county has \(49500\) residents. In the last election, \(54\%\) turned out to vote. How many residents voted?
In the last election, residents in the county turned out to vote.
Answer.
\(26730\)
Solution.
This problem can be boiled down to this question: What is \(54\%\) of \(49500\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(54\%\) of \(49500\) is \(x\text{,}\) so β€œ\(54\) out of \(100\)” corresponds to β€œ\(x\) out of \(49500\)”.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t] \frac{54}{100} \amp = \frac{x}{49500} \\ 100x \amp = 54 \cdot 49500 \\ 100x \amp = 2673000 \\ \frac{100x}{100} \amp = \frac{2673000}{100} \\ x \amp = 26730 \end{aligned} }\)
In the last election, \(26730\) residents in the county. turned out to vote.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(54\%\) of \(49500\text{?}\) Assume \(x\) is \(54\%\) of \(49500\text{.}\) We have:
\(\displaystyle{ \begin{aligned} x \amp = 0.54 \cdot 49500 \\ \amp = 26730 \end{aligned} }\)
In the last election, \(26730\) residents in the county. turned out to vote.
Method 3
In the sentence β€œWhat is \(54\%\) of \(49500\text{,}\)”
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 54\% \cdot 49500 = 0.54 \cdot 49500 = 26730 }\)
In the last election, \(26730\) residents in the county. turned out to vote.

6.

A painting is on sale with \(35\%\) off. Its original price was \({\$400.00}\text{.}\) What is its price on sale?
The painting sells for on sale.
Answer.
\(\$260.00\)
Solution.
The painting is \(35\%\) off, implying that its current price is \(65\%\) of its original price.
This problem can be boiled down to this question: What is \(65\%\) of \(400\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(65\%\) of \(400\) is \(x\text{,}\) so β€œ\(65\) out of \(100\)” corresponds to β€œ\(x\) out of \(400\)”.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t] \frac{65}{100} \amp = \frac{x}{400} \\ 100x \amp = 65 \cdot 400 \\ 100x \amp = 26000 \\ \frac{100x}{100} \amp = \frac{26000}{100} \\ x \amp = 260 \end{aligned} }\)
The painting sells for \({\$260.00}\) on sale.
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(65\%\) of \(400\text{?}\) Assume \(x\) is \(65\%\) of \(400\text{.}\) We have:
\(\displaystyle{ \begin{aligned} x \amp = 0.65 \cdot 400 \\ \amp = 260 \end{aligned} }\)
The painting sells for \({\$260.00}\) on sale.
Method 3
In the sentence β€œWhat is \(65\%\) of \(400\text{,}\)”
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 65\% \cdot 400 = 0.65 \cdot 400 = 260 }\)
The painting sells for \({\$260.00}\) on sale.

7.

A watch’s wholesale price was \({\$260.00}\text{.}\) The retailer marked up the price by \(40\%\text{.}\) What’s the watch’s new price (markup price)?
The watch’s markup price is .
Answer.
\(\$364.00\)
Solution.
First, we need to find the amount of increase in price. It’s given that the watch’s price was marked up by \(40\%\) of its original price, \({\$260.00}\text{.}\)
The problem can be boiled down to this question: What is \(40\%\) of \(260\text{?}\) We will show multiple methods to solve this problem.
Method 1
We will use proportion to solve this problem. Assume \(40\%\) of \(260\) is \(x\text{,}\) so β€œ\(40\) out of \(100\)” corresponds to β€œ\(x\) out of \(260\)”.
We will write and solve the proportion:
\(\displaystyle{\begin{aligned}[t] \frac{40}{100} \amp = \frac{x}{260} \\ 100x \amp = 40 \cdot 260 \\ 100x \amp = 10400 \\ \frac{100x}{100} \amp = \frac{10400}{100} \\ x \amp = 104 \end{aligned} }\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watch’s markup price is \({\$364.00}\text{.}\)
Method 2
We will use the percentage formula to solve this problem. This translation from English to math may help you remember the percentage formula.
\(2 \text{ is } 50\% \text{ of } 4 \iff 2 = 0.5 \cdot 4\)
The question is: What is \(40\%\) of \(260\text{?}\) Assume \(x\) is \(40\%\) of \(260\text{.}\) We have:
\(\displaystyle{ \begin{aligned} x \amp = 0.4 \cdot 260 \\ \amp = 104 \end{aligned} }\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watch’s markup price is \({\$364.00}\text{.}\)
Method 3
In the sentence β€œWhat is \(40\%\) of \(260\text{,}\)”
By the formula \(\text{percentage} = \text{rate} \cdot \text{base}\text{,}\) we do a multiplication to solve the problem:
\(\displaystyle{ \text{percentage } = \text{rate} \cdot \text{base} = 40\% \cdot 260 = 0.4 \cdot 260 = 104 }\)
The amount of price increase was \({\$104.00}\text{,}\) so the new price is \({\$260.00}+{\$104.00}={\$364.00}\text{.}\)
So the watch’s markup price is \({\$364.00}\text{.}\)

11.

Set up a proportion to solve the application problem. Round your answer to the nearest milliliter:
Pediatricians prescribe 60 milliliters (ml) of acetaminophen for every 20 pounds of a child’s weight. How many milliliters of acetaminophen will the doctor prescribe for Jocelyn, who weighs 65 pounds?
Solution: ml (rounded to the nearest ml)
Answer.
Solution.
The ratio given is:
\(\displaystyle{\frac{60 \; \textrm{ml}}{20 \; \textrm{lbs}}}\)
We can set up a ratio, making sure that the units are the same on each side.
\(\displaystyle{\frac{60 \; \textrm{ml}}{20 \; \textrm{lbs}}=\frac{x \; \textrm{ml}}{65 \; \textrm{lbs}}}\)
\(\displaystyle{\frac{60}{20}=\frac{x}{65}}\)
Set the cross products equal:
\(20x = 65\cdot60\)
\(20x = 3900\)
Divide both sides by 20.
\(x = 195\)

12.

Set up a proportion to solve the application problem. Enter a reduced fraction or integer as your final answer.
An oatmeal cookie recipe calls for \(\frac{1}{4}\) cup of butter to make 6 cookies. Hilda needs to make 42 cookies for the bake sale. How many cups of butter will she need?
Solution: cups
Answer.
\({\frac{7}{4}}\)
Solution.
Let x = the number of cups of butter that Hilda needs.
We can use the proportion:
\(\displaystyle{\frac{\frac{1}{4}}{6}=\frac{x}{42}}\)
Set the cross products equal:
\(6x = \frac{1}{4} \cdot 42\)
\(6x = \frac{1}{4} \cdot \frac{42}{1}\)
\(6x = \frac{42}{4}\)
\(x = \frac{42}{4} \div 6\)
\(x = \frac{42}{4} \cdot \frac{1}{6}\)
\(x = \frac{42}{24}\)
\(x = {{\frac{7}{4}}}\)